SQL Schema

The  Employee  table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

Given the  Employee  table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

Solution:


select E1.Name 
from Employee as E1, Employee as E2 
where E1.ManagerId = E2.Id and E1.Salary > E2.Salary
select e.Name as Employee
from Employee e, Employee m
where e.ManagerId is not NULL and
e.ManagerId = m.ID and e.Salary > m.Salary
select a.Name
from Employee a inner join Employee b on a.ManagerId=b.Id
where a.Salary>b.Salary
SELECT Name AS Employee FROM Employee e1
WHERE Salary > (SELECT Salary FROM Employee e2 WHERE e2.Id = e1.ManagerId)
SELECT e1.`Name`
FROM `Employee` e1
LEFT JOIN `Employee` e2 ON(e2.`Id` = e1.`ManagerId`)
WHERE e1.`ManagerId` IS NOT NULL AND e1.`Salary` > e2.`Salary`
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